JJonas Posted December 1, 2011 Posted December 1, 2011 so if just one word is it possible to break it with a dictionary attack?
localzuk Posted December 1, 2011 Posted December 1, 2011 so if just one word is it possible to break it with a dictionary attack? You'd have to create a script to strip out padding and try combinations of letters, and then run them through a dictionary. But with that number of hex pairs, you're going to have a lot of combinations, so potentially a lot of random words...
mac_shinobi Posted December 1, 2011 Posted December 1, 2011 [C] rc4dc.c - http://www.canyoucrackit.co.uk - part #1 - Pastebin.com
bandgeekmafia78 Posted December 1, 2011 Posted December 1, 2011 [C] rc4dc.c - http://www.canyoucrackit.co.uk - part #1 - Pastebin.com Thats what I was referring to. Does this need to be saved into C and compiled?
mac_shinobi Posted December 1, 2011 Posted December 1, 2011 (edited) I'd say yes ( C or some form of C ie C # or C++ ) Im stumped now Edited December 1, 2011 by mac_shinobi
JJonas Posted December 1, 2011 Posted December 1, 2011 Why is the main image a .png when the background image is a .jpg?
LosOjos Posted December 1, 2011 Posted December 1, 2011 Why is the main image a .png when the background image is a .jpg? Looks to me like there's something fishy about that PNG's header, I've been trying to decode it in C# but I'm getting nowhere... gonna have to leave it a while now, already burnt through my lunch on it!
bandgeekmafia78 Posted December 1, 2011 Posted December 1, 2011 Also, if you ctrl+A on the .png you get a message saying "The Challenge Continues". Hmmm...
JJonas Posted December 1, 2011 Posted December 1, 2011 Also, if you ctrl+A on the .png you get a message saying "The Challenge Continues". Hmmm... Try it in firefox you get that without the CTRL+A
featured_spectre Posted December 1, 2011 Posted December 1, 2011 Finally got part 1....now onto part 2!
LeightonJames Posted December 1, 2011 Author Posted December 1, 2011 No way man!! Any pointers you could give?
featured_spectre Posted December 1, 2011 Posted December 1, 2011 Here is what part 2 says! //-------------------------------------------------------------------------------------------------- // // stage 2 of 3 // // challenge: // reveal the solution within VM.mem // // disclaimer: // tested in ie 9, firefox 6, chrome 14 and v8 shell (How to Download and Build V8 - V8 JavaScript Engine - Google Code), // other javascript implementations may or may not work. // //-------------------------------------------------------------------------------------------------- var VM = { cpu: { ip: 0x00, r0: 0x00, r1: 0x00, r2: 0x00, r3: 0x00, cs: 0x00, ds: 0x10, fl: 0x00, firmware: [0xd2ab1f05, 0xda13f110] }, mem: [ 0x31, 0x04, 0x33, 0xaa, 0x40, 0x02, 0x80, 0x03, 0x52, 0x00, 0x72, 0x01, 0x73, 0x01, 0xb2, 0x50, 0x30, 0x14, 0xc0, 0x01, 0x80, 0x00, 0x10, 0x10, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 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0x9a, 0xe3, 0xe6, 0x81, 0xb5, 0xbb, 0xd7, 0xcd, 0x87, 0xa3, 0xd3, 0x6b, 0x36, 0x6f, 0x6f, 0x66, 0x55, 0x30, 0x16, 0x45, 0x5e, 0x09, 0x74, 0x5c, 0x3f, 0x29, 0x2b, 0x66, 0x3d, 0x0d, 0x02, 0x30, 0x28, 0x35, 0x15, 0x09, 0x15, 0xdd, 0xec, 0xb8, 0xe2, 0xfb, 0xd8, 0xcb, 0xd8, 0xd1, 0x8b, 0xd5, 0x82, 0xd9, 0x9a, 0xf1, 0x92, 0xab, 0xe8, 0xa6, 0xd6, 0xd0, 0x8c, 0xaa, 0xd2, 0x94, 0xcf, 0x45, 0x46, 0x67, 0x20, 0x7d, 0x44, 0x14, 0x6b, 0x45, 0x6d, 0x54, 0x03, 0x17, 0x60, 0x62, 0x55, 0x5a, 0x4a, 0x66, 0x61, 0x11, 0x57, 0x68, 0x75, 0x05, 0x62, 0x36, 0x7d, 0x02, 0x10, 0x4b, 0x08, 0x22, 0x42, 0x32, 0xba, 0xe2, 0xb9, 0xe2, 0xd6, 0xb9, 0xff, 0xc3, 0xe9, 0x8a, 0x8f, 0xc1, 0x8f, 0xe1, 0xb8, 0xa4, 0x96, 0xf1, 0x8f, 0x81, 0xb1, 0x8d, 0x89, 0xcc, 0xd4, 0x78, 0x76, 0x61, 0x72, 0x3e, 0x37, 0x23, 0x56, 0x73, 0x71, 0x79, 0x63, 0x7c, 0x08, 0x11, 0x20, 0x69, 0x7a, 0x14, 0x68, 0x05, 0x21, 0x1e, 0x32, 0x27, 0x59, 0xb7, 0xcf, 0xab, 0xdd, 0xd5, 0xcc, 0x97, 0x93, 0xf2, 0xe7, 0xc0, 0xeb, 0xff, 0xe9, 0xa3, 0xbf, 0xa1, 0xab, 0x8b, 0xbb, 0x9e, 0x9e, 0x8c, 0xa0, 0xc1, 0x9b, 0x5a, 0x2f, 0x2f, 0x4e, 0x4e, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00 ], exec: function() { // virtual machine architecture // ++++++++++++++++++++++++++++ // // segmented memory model with 16-byte segment size (notation seg:offset) // // 4 general-purpose registers (r0-r3) // 2 segment registers (cs, ds equiv. to r4, r5) // 1 flags register (fl) // // instruction encoding // ++++++++++++++++++++ // // byte 1 byte 2 (optional) // bits [ 7 6 5 4 3 2 1 0 ] [ 7 6 5 4 3 2 1 0 ] // opcode - - - // mod - // operand1 - - - - // operand2 - - - - - - - - // // operand1 is always a register index // operand2 is optional, depending upon the instruction set specified below // the value of mod alters the meaning of any operand2 // 0: operand2 = reg ix // 1: operand2 = fixed immediate value or target segment (depending on instruction) // // instruction set // +++++++++++++++ // // Notes: // * r1, r2 => operand 1 is register 1, operand 2 is register 2 // * movr r1, r2 => move contents of register r2 into register r1 // // opcode | instruction | operands (mod 0) | operands (mod 1) // -------+-------------+------------------+----------------- // 0x00 | jmp | r1 | r2:r1 // 0x01 | movr | r1, r2 | rx, imm // 0x02 | movm | r1, [ds:r2] | [ds:r1], r2 // 0x03 | add | r1, r2 | r1, imm // 0x04 | xor | r1, r2 | r1, imm // 0x05 | cmp | r1, r2 | r1, imm // 0x06 | jmpe | r1 | r2:r1 // 0x07 | hlt | N/A | N/A // // flags // +++++ // // cmp r1, r2 instruction results in: // r1 == r2 => fl = 0 // r1 < r2 => fl = 0xff // r1 > r2 => fl = 1 // // jmpe r1 // => if (fl == 0) jmp r1 // else nop throw "VM.exec not yet implemented"; } }; //-------------------------------------------------------------------------------------------------- try { VM.exec(); } catch(e) { alert('\nError: ' + e + '\n'); } //--------------------------------------------------------------------------------------------------
LeightonJames Posted December 1, 2011 Author Posted December 1, 2011 Well, that's me out then!! lol No idea at all what the hell that lot means!!
CHR1S Posted December 1, 2011 Posted December 1, 2011 There is a hidden cypher in the PNG header. The code is x86. The second page is a VM that needs to be compiled and run. This message will self destruct in 10 seconds.....
featured_spectre Posted December 1, 2011 Posted December 1, 2011 Stage 3 is NOT the website...its another fricken test!
LeightonJames Posted December 1, 2011 Author Posted December 1, 2011 GO ON nephilim, You can do it!!!
featured_spectre Posted December 1, 2011 Posted December 1, 2011 it kicks in after you do the VM... *edit* if you think the first one is tough, the last one is even harder, its done based on your name, so no 2 should be the same! Absolute nightmare!
LeightonJames Posted December 1, 2011 Author Posted December 1, 2011 I'm impressed you have got this far TBH. I gave up at the first stage. I hope you manage to solve this one
mac_shinobi Posted December 1, 2011 Posted December 1, 2011 I never got passed the first stage either, sigh
CHR1S Posted December 1, 2011 Posted December 1, 2011 Pfft too easy... SPOILER BTW... Can you crack it?
X-13 Posted December 2, 2011 Posted December 2, 2011 I got to figuring out the code was x86... then gave up. From what I've heard the job isn't that good anyway.
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