My Question is how do I change ' to ' via the xsl?

My Question is how do I change ' to ' via the xsl?

In ie i get Community Nurse — Children and Young People's Directorate

In opera i get Community Nurse — Children and Young People's Directorate

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Hi I have the following XML

XML Code:
<?xml version="1.0" encoding="ISO-8859-1"?>

<!DOCTYPE nhs_search [
<!ELEMENT nhs_search (status, vacancy_details*) >

<!ELEMENT status (number_of_jobs_found, message*)>
<!ELEMENT number_of_jobs_found (#PCDATA)>
<!ELEMENT message (#PCDATA)>

<!ELEMENT vacancy_details (id, job_reference, job_title, job_description, job_specialty?, job_salary, job_location, job_closedate, job_postdate, job_url)>
<!ELEMENT id (#PCDATA)>
<!ELEMENT job_reference (#PCDATA)>
<!ELEMENT job_title (#PCDATA)>
<!ELEMENT job_description (#PCDATA)>
<!ELEMENT job_specialty (#PCDATA)>
<!ELEMENT job_salary (#PCDATA)>
<!ELEMENT job_location (#PCDATA)>
<!ELEMENT job_closedate (#PCDATA)>
<!ELEMENT job_postdate (#PCDATA)>
<!ELEMENT job_url (#PCDATA)>
]>

<nhs_search>

<status>
<number_of_jobs_found>20</number_of_jobs_found>
<message></message>
</status>

<vacancy_details>
<id>912080005</id>
<job_reference>346-CYP-01</job_reference>
<job_title>Community Nurse</job_title>
<job_description>An opportunity has arisen within the service for an additional Community Nurse. The Children and Young People’s Service provides a specialist mental health, community based approach to young people, 0-17th year. The service operates as a multi-disciplinary team; nursing psychology and psychiatry, who work together to provide an effective service. The Community Nursing Service works within a multi-agency framework and...</job_description>
<job_specialty>Children and Young People&apos;s Directorate</job_specialty>
<job_salary>&#16324,103 - &#16332,653 pr pa</job_salary>
<job_location>County Durham</job_location>
<job_closedate>05/09/2008</job_closedate>
<job_postdate>22/08/2008</job_postdate>
<job_url>http://www.jobs.nhs.uk/cgi-bin/vacdetails.cgi?selection=912080005</job_url>
</vacancy_details>

</nhs_search>

which gets transformed by the following XSL

XML Code:


<!DOCTYPE xsl:stylesheet [
<!ENTITY nbsp "*">
<!ENTITY copy "©">
<!ENTITY reg "®">
<!ENTITY trade "™">
<!ENTITY mdash "—">
<!ENTITY ldquo "“">
<!ENTITY rdquo "”">
<!ENTITY pound "£">
<!ENTITY yen "¥">
<!ENTITY euro "€">
<!ENTITY apos "'">
]>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:wpc="com.sap.nw.wpc.km.service.linkmanager.X sltHelper">

<xsl:output method="html"/>

<xsl:template match="/">
<xsl:for-each select="nhs_search/vacancy_details">

<xsl:variable name="apos"><xsl:text
disable-output-escaping="yes">'</xsl:text></xsl:variable>

<xsl:value-of select="job_title" disable-output-escaping="yes"/> — <xsl:value-of select="job_specialty" disable-output-escaping="yes"/>

<xsl:value-of select="job_postdate" disable-output-escaping="yes"/> / <xsl:value-of select="job_closedate" disable-output-escaping="yes"/>
<xsl:value-of select="job_reference" disable-output-escaping="yes"/> 
<xsl:value-of select="job_salary" disable-output-escaping="yes"/>
<xsl:value-of select="job_description"/>
<xsl:value-of select="job_url" disable-output-escaping="yes"/>
<hr />
</xsl:for-each>

</xsl:template>
</xsl:stylesheet>
Resulting in

HTML Code:
Community Nurse — Children and Young People's Directorate

22/08/2008 / 05/09/2008

346-CYP-01

£24,103 - £32,653 pr pa

An opportunity has arisen within the service for an additional Community Nurse. The Children and Young People’s Service provides a specialist mental health, community based approach to young people, 0-17th year. The service operates as a multi-disciplinary team; nursing psychology and psychiatry, who work together to provide an effective service. The Community Nursing Service works within a multi-agency framework and...

Error Page Question is how do I change ' to ' via the xsl?

I have googled and googled and googled this to no avail any help and assistance will be greatfully recieved.

The XML cannot be modyfied and comes from

http://www.jobs.nhs.uk/extsearch?cli...ly=n&infonly=1

Thank you in advance

Regards

Damien

try this:

Code:

<xsl:template name="escape-apos"> <xsl:param name="string"/> <xsl:variable name="apos" select='"'"' /> <xsl:choose> <xsl:when test='contains($string, $apos)'> <xsl:value-of select="substring-before($string,$apos)" /> <xsl:text>\'</xsl:text> <xsl:call-template name="escape-apos"> <xsl:with-param name="string" select="substring-after($string, $apos)" /> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$string" /> </xsl:otherwise> </xsl:choose> </xsl:template>

:o = : & o
:p = : & p (without spaces)... :)

Use the code tags they are available in the advanced editor.

Ben

:) couldn't see the wood for the trees.

My Question is how do I change &apos; to ' via the xsl?

My Question is how do I change ' to ' via the xsl?