I'm getting nowhere, put it all in HxD but it was never going to be that easy was it?
@nephilim - really intrigued how you got "Infinity"? The numbers involved seem too large to convert to ASCII...
Infinity is 49:6e:66:69:6e:69:74:79 in Hex
Assuming this is Hexadecimal base 16, the 'easiest' solution is to assume it's ASCII character table.
From this, hex code '20' would be a space, and '48' to '57' would be numbers, '41' to '5A' would be uppercase letters, and '61' to '7A' would be lowercase letters. I would be highly surprised if there was non-alphabetical letters in there, so anything not in these ranges is unlikely to be real.
Anything higher than 7A does not on ASCII convert into a letter. It could in theory be EBCDIC, which is an older style character conversion used in punch cards in the 60's which goes up to FF in hex.
Beyond this I'm out of ideas, and haven't had a chance to have a go myself, but that's the best idea's I've got.
Chances are, that there is a lot of rubbish filler, and it's worth looking for a pattern within it for the gibberish as well as the coding above.
There are also probably more hex code conversions, but I'm not immediately aware of them.
closest I got was this :
Can you crack it? - GCHQ - Overclockers UK Forums
'we will be in touch'
Was trying to establish if there was a way to download the asp file ( index.asp ) and view the source code from the asp page
My theory is that if you can somehow plot the Hex onto a graph on a scientific calculator, the hex might 'curve' to shape/draw letters on the graph. A bit like SIN/COS/TAN
I'm probably thinking too hard about this now.
Wow, glad to see that this has piqued some interest!!
Apparently it is only one word and there is a hell of a lot of padding in the hex string.
Even armed with that information i don't know what to do
Someone has put some extra information on pastebin, but even with that information I'm a long way from cracking it
If anyone wants that info PM me and I'll send it across.
so if just one word is it possible to break it with a dictionary attack?
There are currently 1 users browsing this thread. (0 members and 1 guests)