I think I have an answer, but can't find a definite answer on google.
link to an answer page if possible?
Edit: Found the answer I was wrong
the answer is here http://xkcd.com/solution.html for anyone interested
or "an" answer
I could not work this one out... see if any of you can.
The answer can be found using google if you can't work it out and get curious.
A group of people with assorted eye colors live on an island. They are all perfect logicians -- if a conclusion can be logically deduced, they will do it instantly. No one knows the color of their eyes. Every night at midnight, a ferry stops at the island. Any islanders who have figured out the color of their own eyes then leave the island, and the rest stay. Everyone can see everyone else at all times and keeps a count of the number of people they see with each eye color (excluding themselves), but they cannot otherwise communicate. Everyone on the island knows all the rules in this paragraph.
On this island there are 100 blue-eyed people, 100 brown-eyed people, and the Guru (she happens to have green eyes). So any given blue-eyed person can see 100 people with brown eyes and 99 people with blue eyes (and one with green), but that does not tell him his own eye color; as far as he knows the totals could be 101 brown and 99 blue. Or 100 brown, 99 blue, and he could have red eyes.
The Guru is allowed to speak once (let's say at noon), on one day in all their endless years on the island. Standing before the islanders, she says the following:
"I can see someone who has blue eyes."
Who leaves the island, and on what night?
There are no mirrors or reflecting surfaces, nothing dumb. It is not a trick question, and the answer is logical. It doesn't depend on tricky wording or anyone lying or guessing, and it doesn't involve people doing something silly like creating a sign language or doing genetics. The Guru is not making eye contact with anyone in particular; she's simply saying "I count at least one blue-eyed person on this island who isn't me."
And lastly, the answer is not "no one leaves."
I think I have an answer, but can't find a definite answer on google.
link to an answer page if possible?
Edit: Found the answer I was wrong
the answer is here http://xkcd.com/solution.html for anyone interested
or "an" answer
Last edited by rolfea; 4th June 2009 at 12:49 PM.
Lunchtime puzzle? I think I need to talk to your boss on how long you get for lunch if you wrapped your head around that without looking up the solution in a lunch break!!
the person running the ferry, and every night
te other way to look at it logically is by reading a few bits
so there is a solution...yes...THEY get it straight away, they all leave. it doesnt ask how do they figure it out, just who and when.They are all perfect logicians -- if a conclusion can be logically deduced, they will do it instantly
so as they will figure it out "instantly" the answer [logically] is....
every one leaves on the 1st night
simple
All of the blue-eyed people leave that night.
I think I've got the answer, but I don't want to spoil it for everyone else.
Bat, I'll PM you with it.
Last edited by jamesb; 4th June 2009 at 01:36 PM. Reason: Adding more
thats what I thought, but supposedly i'm wrong
which (logically) makes you wrong
That solution seems very flawed to me. I just cannot see a way for that solution to work. Well it works with low numbers but not the numbers we are given.
EDIT:
The more I think about it the more the solution seems wrong. According to the logic in the solution everyone will leave thinking they have blue eyes even if they have not.
I understand how the solution can work with low numbers, but say there are 11 blue eyed people. That means each blue eyed person see 10 other blue eyed people. No one can leave as they all see 10 other people with blue eyes. So the 11th person has no idea if their eyes are blue, red, green or whatever.
Last edited by Pottsey; 4th June 2009 at 02:17 PM.
Could someone explain via PM?
I've read the solution. It makes perfect sense to me - never would have come up with the answer in a million years! But, I'm now left feeling very sorry for the Guru...
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